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    Home > Chemicals Industry > Chemical Technology > Application of Free Energy-Oxidation Number Diagram

    Application of Free Energy-Oxidation Number Diagram

    • Last Update: 2021-06-18
    • Source: Internet
    • Author: User
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    1) Judging the redox ability of different oxidation states

    In the free energy-oxidation number diagram, the slope of each line segment is different
    .


    Investigation segment the IO .


    The corresponding electrode reaction is

    From ②-③, we get

    Obviously

    Therefore, the line segment the IO .


    3
    - -IO - slope molecules couple the IO .
    3
    - / the IO - standard free energy change electrode reaction rGm in △ [Theta] @ a negative slope denominator couple the IO .
    3
    - / the IO - electrode reaction The number of electron transfers z


    Substituting △rGm Θ =-zFE Θ into the above formula, we get

    k=FE Θ

    The above formula shows that the slope k of the line segment in the free energy oxidation number graph is proportional to the standard electrode potential E Θ of the electrical pair composed of the oxidation states at both ends of the line segment
    .


    Therefore, the greater the slope of the line segment in the figure, the stronger the oxidizing ability of the oxidizing type of the electric pair; the smaller the slope of the line segment, the stronger the reducing ability of the reducing type of the electric pair


    In the above-described iodine in alkaline medium free energy - FIG oxidation number, H .


    3
    the IO .


    2) Judging the possibility of disproportionation reaction

    Iodine in free energy - FIG oxidation number, the I 2 different slope segments on both sides of a single substance, the I 2 -I - the slope is greater than the IO - -I 2 slope, indicating couple I2 / the I - electrode potential is greater than the couple the IO - / the I 2 electrode potential
    .


    That is, the electrode potential of I2 as an oxidizing pair is greater than its electrode potential as a reducing type.


    The I 2 + 2OH - = the I - + the IO - + H 2 O

    This discussion is intuitively reflected in the free energy-oxidation number diagram.


    According to the above discussion, IO - and I 2 are unstable in alkaline medium, and disproportionation reaction occurs; IO 3 -is stable, and disproportionation reaction does not occur


     

     

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