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    Home > Chemicals Industry > Chemical Technology > Chemical reaction isotherm and the relationship between KΘ and =△rGmΘ

    Chemical reaction isotherm and the relationship between KΘ and =△rGmΘ

    • Last Update: 2021-06-18
    • Source: Internet
    • Author: User
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    4.
    2.
    1 Chemical reaction isotherm

    If react

    The Gibbs free energy of the reaction at any time is △ r G m , and the reaction relative quotient is Q Θ , then

    r G m =△ r G m Θ +RTInQ Θ

    This is the chemical reaction isotherm
    .


    The origin, derivation and physical meaning of this relationship will be studied in physical chemistry


    4.


    2.


    When the system is in equilibrium

    r G m =0 Q Θ =K Θ

    Substituting into the chemical reaction isotherm formula, we get

    0=△ r G m Θ +RTInK Θ

    which is

    r G m Θ =-RTInk Θ

    The relationship establishes the relationship between the standard Gibbs free energy change △ r G m Θ and the standard equilibrium constant, and the standard equilibrium constant KΘ of chemical reactions can be calculated from the thermodynamic data △ r G m Θ
    .

    Substituting the formula △ r G m Θ =-RTInK Θ into the chemical reaction isothermal formula △ r G m =△ r G m Θ +RTInQ Θ , we have

    r G m =-RTInK Θ +RTInQ Θ

    Organized

    This formula relates the Gibbs free energy change △ r G m when the reaction is in a non-standard state and the ratio of the reaction relative quotient Q Θ to the standard equilibrium constant K Θ .


    The sign of △ r G m can be judged according to the magnitude of the ratio .


    When Q Θ <K Θ , △ r G m <0, the reaction proceeds forward

    When Q Θ = K Θ , △ r G m =0, the reaction reaches equilibrium

    When Q Θ >K Θ , △ r G m >0, the reaction proceeds in reverse

    [Example 4-4] After mixing 1 mol SO 2 , 2 mol O 2 and 7 mol Ne, the gas reacts under normal pressure

    The reaction reaches equilibrium at 912K, and 70% of SO 2 is converted to SO 3 to obtain the reaction △ r G m Θ
    .

    The solution is based on the reaction equation, the amount of substance in each gas after the reaction equilibrium is

    The total amount of substances in the gas after the reaction is

    n=nso 2 +nO 2 +nso 3 +n Ne =9.


    65 mol

    The mole fraction of each gas after the reaction is


    According to the gas partial pressure law, the partial pressure of a gas is equal to the product of its mole fraction and the total pressure, then the partial pressure of each gas after the reaction


    The standard equilibrium constant of the reaction is


    and so


     

     

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