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    The relationship between reactant concentration and reaction time-zero order reaction

    • Last Update: 2021-06-18
    • Source: Internet
    • Author: User
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    Chemical kinetics not only pays attention to the influence of reactant concentration on the reaction rate, but also pays attention to the change of reactant concentration over time
    .


    Using the differential expression of the reaction rate equation to derive the corresponding integral expression, the relationship between reactant concentration and time can be obtained


    1.
    Zero-order reaction

    The characteristic of the zero-order reaction is that the reaction rate has nothing to do with the concentration of the reactants
    .


    A zero-order reaction

    A=B

    If the reaction rate is expressed by the change in the concentration of reactant A, the differential expression of the reaction rate equation is

    Organize, get

    -d[A]=kdt

    If the initial concentration of reactant A is [A] 0 , and the concentration at time t is [A] t , integrate both sides of the above formula at the same time

    Get

    [A] t -[A] 0 =-k t

    Organize, get

    [A] t =[A] 0 -k t

    The above two formulas are the integral expressions of the zero-order reaction
    .


    If the initial concentration of the reactant and the rate constant k are known, the concentration of the reactant at any time can be obtained through the integral expression


    The integral expression of the zero-order reaction can also be written as

    [A] 0 -[A] t =k t

    That is, the change in reactant concentration is proportional to time
    .


    This is one of the characteristics of the zero-order reaction


    [Example 3-2] Reaction A=B is a zero-order reaction, and reactant A consumes 25% in 100 minutes
    .


    Calculate how much reactant A consumes at 200 min


    Solve and set [A] 0 =1mol·dm -3 , then [A] 100 mim =0.


    75mol·dm -3


    [A] t =[A] 0 -k t

    Get

    0.
    75=1-k×100

    k=2.
    5×10 -3 (mol·dm -3 .
    min -1 )

    At 200min

    [A] 200 mim =1-2.
    5×10 -3 ×200=0.
    5(mol·dm -3 ), 50% consumed

    Another solution:

    by

    [A] 0 -[A] t =kt

    At 100min

    [A] 0 -[A] 100 min =k×100

    At 200min

    [A] 0 -[A] 100 mim=k×200

    Divide the two formulas, get

    [A] 200 min=0.
    5(mol·dm -1 ), 50% consumed

    The reaction was consumed half the time required for the half-life is called, with T 1/2 expressed
    .


    The size of the half-life can also reflect the speed of the reaction rate.


    Substitute the concentration when the reaction reaches the half-life [A] t =1/2[A] 0 into the zero-order reaction integral expression

    1/2[A] 0 =[A] 0 -kt 1/2

    Organize, get


    It can be seen that the half-life of the zero-order reaction is directly proportional to the initial concentration of the reactants and inversely proportional to the rate constant of the reaction


    Related link: The influence of reactant concentration on reaction

     

     

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