-
Categories
-
Pharmaceutical Intermediates
-
Active Pharmaceutical Ingredients
-
Food Additives
- Industrial Coatings
- Agrochemicals
- Dyes and Pigments
- Surfactant
- Flavors and Fragrances
- Chemical Reagents
- Catalyst and Auxiliary
- Natural Products
- Inorganic Chemistry
-
Organic Chemistry
-
Biochemical Engineering
- Analytical Chemistry
- Cosmetic Ingredient
-
Pharmaceutical Intermediates
Promotion
ECHEMI Mall
Wholesale
Weekly Price
Exhibition
News
-
Trade Service
7 Analysis steps
7.
7.
Weigh the mass of a 100mL screw-top bottle with septum to the nearest 0.
Mass m impurity gas component i i , values in grams (g), calculated according to formula (1):
Where:
V i ——The gas volume of the added impurity centimetre i, in milliliters (mL);
M i ——The molar mass of the added impurity component i, in grams (g);
24450——The volume of 1 mole of gas at 25°C and 101.
M mass of the liquid of impurity components i i .
mi=p i V i .
Where:
V i ——the liquid volume of added impurity component i, in milliliters (mL);
p i ——The density of the added impurity component i, in grams per milliliter (g/mL)
7.
The mass fraction w i of impurity component i in the calibration standard sample , the value is expressed in %, calculated according to formula (3):
Where:
m i ——the mass of impurity component i in the calibration standard sample, in grams (g);
m——The mass of the wood bottom sample in the calibration standard sample, in grams (g)
7.
Take a quantitative standard sample for calibration, measure it according to the selected chromatographic operating conditions, and measure the corresponding methyl chloride background sample at the same time
Where:
w i ——the mass fraction (%) of impurity component i in the calibration standard sample;
△A i ——the impurity component in the calibration standard sample: the difference between the peak area of the peak area and the peak area of the impurity component i in the corresponding background sample;
wR——The mass fraction of reference substance R (%);
R AR-- peak area of reference
7.
7.
7.
2 Determination of samples
Take a liquid sample for determination according to the selected chromatographic operating conditions
.
8 Result calculation
The content of methyl chloride is calculated as the mass fraction w 1 and the value is expressed as %, calculated according to formula (5):
Where
A i ——the peak area of component i;
f i ——The relative mass correction factor of component i;
wH 2 O——The mass fraction of water in the methyl chloride sample
.
Take the arithmetic mean of the two parallel determination results as the determination result
.
The absolute difference between the two parallel determination results of the main content is not more than 0.
02%
.
When the mass fraction of impurities is less than or equal to 0.
01%, the absolute difference between the two parallel determination results shall not be greater than 20% of the average of the two parallel determination results
.
When the mass fraction of impurities is greater than 0.
01%, the absolute difference between the two parallel determination results shall not be greater than 10% of the average value of the two parallel determination results
.
Related Links: Determination of Purity of Methyl Chloride Products for Industrial Use-Gas Chromatography (1)