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    Home > Chemicals Industry > Chemical Technology > Reduction of carbon element

    Reduction of carbon element

    • Last Update: 2021-06-17
    • Source: Internet
    • Author: User
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    Carbon element can reduce non-metal oxides and metal oxides
    .


    Carbon and CO as reducing agents have the following three reactions


    From the Gibbs formula △rGm Θ = △rHm Θ -T△rSm Θ , the reaction △rGm Θ product versus temperature T is plotted (Figure 13-2), and 3 straight lines are obtained.


    The slope of the line segment is -△rSm Θ


    The reaction of metal with oxygen, taking manganese as an example

    Figure 13-2 carbon as reductant and oxygen to react with the manganese rGm in △ [Theta] - Line

    It can be seen from Figure 13-2 that the slope of the reaction line for increasing entropy is negative, and the slope of the reaction line for decreasing entropy is positive
    .


    The slope of reaction (d) becomes larger after the inflection point M, indicating that the entropy becomes smaller, that is, the M point is the melting point of Mn instead of the melting point of MnO


    MnO+C=Mn+CO (e)

    Explain that when the temperature T>Ty, the reaction (e) △rGm Θ <0, C can reduce MnO and generate CO
    .

    When the temperature is Tz, the two lines (b) and (d) intersect.
    At this time, the △rGm Θ of the two reactions are equal, and the reactions (b) and (d) are subtracted to obtain the reaction (f)

    2MnO+C=2Mn+CO 2 (f)

    Explain that when the temperature T>Tz, the reaction (f) △rGm Θ black <0, C can reduce MnO and generate CO 2
    .


    Much higher than the temperature Tz Ty, it is mainly the C to CO instead of MnO restore CO 2


    If the ΔrGm Θ -T line where the metal reacts with oxygen does not intersect the (c) or (b) line, the metal cannot be smelted by the C reduction method
    .


    If the △rGm Θ -T line of the reaction between metal and oxygen intersects with line (c) or (b) at a very high temperature, it is not suitable to use C reduction method to smelt the metal


    Since reaction (c) is an exothermic reaction and a process of increasing entropy, the free energy of the reaction is not only negative, but also gradually decreases as the temperature rises, so the reaction can be combined with some non-spontaneous reactions, The overall reaction proceeded spontaneously
    .


    E.


    SiO 2 +2C1 2 =SiCl 4 +O 2

    Since SiO 2 is more stable than SiCl 4 , the reaction is not spontaneous, but it is combined with reaction (c), namely

    SiO 2 +2C+2C1 2 =SiCl 4 +2CO

    It is equivalent to adding some coke to the SiO 2 chlorination reaction, and the total reaction progresses spontaneously with △rGm Θ <0
    .

    This approach is reaction coupling in thermodynamics
    .


    The conversion from B 2 O 3 to BCl 3 and the conversion from TiO 2 to TiCl 4 require coupling


     

     

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